PromptPlus API:Style
Style
Namespace: PPlus
Represents the Style : Colors and overflow strategy.
public struct Style
Inheritance Object → ValueType → Style
Implements IEquatable<Style>
Properties
Background
Gets the background color.
public Color Background { get; }
Property Value
Default
Gets a Style with the default colors and overflow.None
public static Style Default { get; }
Property Value
Foreground
Gets the foreground color.
public Color Foreground { get; }
Property Value
OverflowCrop
Gets a Style with the default colors and overflow Crop.
public static Style OverflowCrop { get; }
Property Value
OverflowEllipsis
Gets a Style with the default colors and overflow Ellipsis.
public static Style OverflowEllipsis { get; }
Property Value
OverflowStrategy
Gets the Overflow strategy.
public Overflow OverflowStrategy { get; }
Property Value
Constructors
Style()
create a new Style with default foreground/background colors and none overflow strategy.
Style()
Style(Color, Overflow)
Create a new instance of Style with foreground, default backgroundcolors and overflow strategy.
Style(Color foreground, Overflow overflowStrategy)
Parameters
foreground Color
Color foreground
overflowStrategy Overflow
Overflow Strategy
Style(Color, Color, Overflow)
Create a new instance of Style with foreground/background colors and overflow strategy.
Style(Color foreground, Color background, Overflow overflowStrategy)
Parameters
foreground Color
Color foreground
background Color
Color background
overflowStrategy Overflow
Overflow Strategy
Methods
Combine(Style)
Combines this style with another one.
Style Combine(Style other)
Parameters
other Style
The item to combine with this.
Returns
A new style representing a combination of this and the other one.
Equals(Style)
Checks if two Style instances are not equal.
bool Equals(Style other)
Parameters
other Style
The Style instance to compare.
Returns
true if the two Style are not equal, otherwise false.
Equals(Object)
bool Equals(object obj)
Parameters
obj Object
Returns
GetHashCode()
int GetHashCode()